(4x^2+22x-12)/(x-16)

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Solution for (4x^2+22x-12)/(x-16) equation: 


D( x )

x-16 = 0

x-16 = 0

x-16 = 0

x-16 = 0 // + 16

x = 16

x in (-oo:16) U (16:+oo)

(4*x^2+22*x-12)/(x-16) = 0

4*x^2+22*x-12 = 0

2*(2*x^2+11*x-6) = 0

2*x^2+11*x-6 = 0

DELTA = 11^2-(-6*2*4)

DELTA = 169

DELTA > 0

x = (169^(1/2)-11)/(2*2) or x = (-169^(1/2)-11)/(2*2)

x = 1/2 or x = -6

2*(x+6)*(x-1/2) = 0

(2*(x+6)*(x-1/2))/(x-16) = 0

( x+6 )

x+6 = 0 // - 6

x = -6

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

x in { -6, 1/2 }

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